The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » Software » comp.soft-sys.matlab

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: selection of combination under required conditions
Replies: 0  

Advanced Search

Back to Topic List Back to Topic List  
sathish kumar

Posts: 17
Registered: 7/24/12
selection of combination under required conditions
Posted: Jan 2, 2013 6:24 AM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

i want to find out combination that are satisfieng my conditions i.e
a1=12; b1=5; c1=5;
a2=13; b2=6; c2=2;
a3=14; b3=7; c3=8;
a4=15; b4=8; c4=9;
r=14; h=7;
my condition is i want choose the combination that r>=a(i) and h>=b(i) and c should be max(i) i.e, if i found 3 combination say( (a1,b1,c1) (a2,b2,c2) (a3,b3,c3) )
satisfies above conditions i.e, r>=a(i) and h>=b(i)
and from these combination ,i want to choose the combination that has maximum 'c' value.
in example
a1=12; b1=5; c1=5;
a2=13; b2=6; c2=2;
a3=14; b3=7; c3=8;
here first two combination satisfies our condition i.e,r>=a(i) and h>=b(i),but the value of c is not maximum of total combinations
here we have selected 3rd combination because it satisfies conditions i.e,r>=a(i) and h>=b(i) and as well as it has maximum C value

i have written code but it not giving the proper results
for i=1:length(set)
if r >= a(i);
if h >= b(i);
if maxc == c(i);
selected = i;
choosen_set = dt{selected}

in this code i am getting the combination that satisfies r>=a(i) and h>=b(i), but not combination that has maximum c value from the found combinations i.e i am gaetting the combination a2=13; b2=6; c2=2; instead of combination a3=14; b3=7; c3=8;

please help me in this code ,i have tried but i am getting correct results
thanks in advance

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.