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Topic: The Math is still Not Ready
Replies: 8   Last Post: Mar 19, 2013 10:35 AM

 Messages: [ Previous | Next ]
 J. Antonio Perez M. Posts: 2,736 Registered: 12/13/04
Re: The Math is still Not Ready
Posted: Jan 6, 2013 7:27 AM

On Sunday, January 6, 2013 7:36:26 AM UTC+2, Koobee Wublee wrote:
> On Jan 5, 8:54 am, Tom Roberts wrote:
>
>
>

> > Here is General Relativity:
>
> >
>
> > On a 4-d Lorentzian manifold M,
>
> > G = T
>
> >
>
> > where G is the Einstein curvature tensor and T is the energy-momentum tensor.
>
>
>
> Please allow Koobee Wublee reminds Tom where that overly simplified
>
> equation[s] above come from. Let?s follow Hilbert?s footsteps and
>
> pull out the following so-called Lagrangian out of Hilbert?s ass.
>
>
>
> ** L = (R / K + rho) sqrt(-det[g])
>
>
>
> Where
>
>
>
> ** L = Lagrangian
>
> ** R = Ricci scalar
>
> ** K = Constant
>
> ** rho = Mass density
>
> ** [g] = The metric (a 4x4 matrix)
>
> ** det[] = Determinant of a matrix
>
>
>
> For the language of convention in this case, [A] means a matrix with
>
> elements [A]_ijk... or [A]^ijk...
>
>
>
> The field equations can be derived in just one step by taking the
>
> partial derivative of the Lagrangian above with respect to [g^-1]^ij
>
> where [g^-1], a matrix, is the inverse of [g], another matrix, and
>
> after setting each of the partial derivative to null, the result is
>
> the following relationships of matrices.
>
>
>
> ** [R] ? R [g] / 2 = K rho [g] / 2
>
>
>
> Where
>
>
>
> ** [R] = Ricci tensor (another 4x4 matrix)
>
>
>
> You would call the following.
>
>
>
> ** [G] = [R] ? R [g] / 2
>
> ** [T] = K rho [g] / 2
>
>
>
> Thus,
>
>
>
> ** [G] = [T]
>
>
>
> Koobee Wublee would also like to remind Tom that the above equation
>
> has never been tested with any experimentations, and the best Tom can
>
> hope for is the following where the energy momentum tensor is null.
>
>
>
> ** [G] = 0
>
>
>
> Where
>
>
>
> ** [T] = 0
>
>
>
> Using only diagonal [g], the equation above simplifies into the
>
> following where the effect of the ever so celebrated trace term is
>
> nullified. The null Ricci tensor was basically Nordstrom?s work where
>
> Schwarzschild had been working on the solution for years. That is why
>
> within a couple months after Hilbert presented the field equations,
>
> Schwarzschild published a solution.
>
>
>
> ** [R] = 0, first proposed by Nordstrom as the field equations
>
>
>
> Where
>
>
>
> ** R [g] / 2 = The trace term
>
>
>
> <shrug>
>
>
>

> > To get SR from GR:
>
> >
>
> > Riemann = 0
>
> > Top(M) ~ R^4
>
> >
>
> > where Riemann is the Riemann curvature tensor on M, and Top(M) is the topology of M.
>
>
>
> Nonsense, Tom. If the Riemann tensor is null, the Ricci tensor must
>
> be null as well in which you end up with the null Ricci tensor above
>
> where you can solve for the Schwarzschild metric and other equally
>
> valid solutions that are able to degenerate into Newtonian law of
>
> gravity at weak curvature in spacetime. <shrug>
>
>
>
> The best way to get SR from GR is to set the gravitating mass, M, to
>
> 0, duh! <shrug>
>
>
>
> ** ds^2 = c^2 (1 ? 2 U) dt^2 ? dr^2 / (1 ? 2 U) ? r^2 dO^2
>
>
>
> Where
>
>
>
> ** U = G M / c^2 / r
>
>
>

> > [Note that approximations are important in applying the theory,
>
> > as this is PHYSICS, not math. Based on your writings around
>
> > here, and your aversion to any intellectual effort, I estimate
>
> > you will never understand this.]
>
>
>
> Tom, in GR, physics = math, and math = physics. So, start
>
> understanding the mathematics involved instead of wishing for what you
>
> believe in. <shrug>
>
>
>
> Faith should not come into any equations of science, no? <shrug>

IDIOT

Date Subject Author
1/6/13 Koobee Wublee
1/6/13 J. Antonio Perez M.
1/7/13 Koobee Wublee
3/17/13 John Polasek
3/18/13 Koobee Wublee
3/19/13 John Polasek