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Replies: 2   Last Post: Jan 12, 2013 9:18 PM

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 Kevin Ellis Posts: 62 Registered: 11/29/10
Posted: Jan 12, 2013 9:18 PM

"james bejon" wrote in message <kcq075\$ant\$1@newscl01ah.mathworks.com>...
> Datasets can be a bit fiddly at times.
>
> I don't have Matlab to hand so will have to go by memory.
>
> In my opinion, the key to working with datasets is to understand that indexing a dataset via normal indexing methods returns a dataset but indexing it via a "dot" extension can return a single column as a non-dataset item, e.g.:
>
> % Define a dataset as follows [hopefully I've got this right]
> ds = dataset( {rand(10, 1), repmat({'strs'}, 10, 1) }, 'VarNames', {'A', 'B'} )
>
> % Now, the following syntax returns a vector of doubles
> X = ds.A;
> whos X
>
> % But this syntax returns a dataset
> X = ds(:, 1);
> whos X
>
> % Which means this is valid:
> ds.A = rand(10, 1) * 5;
>
> % But this isn't:
> ds(:, 1) = rand(10, 1) * 5;
> % because you've got a dataset on the LHS but a vector of double on the RHS
>
> % So to concat:
> ds.B = strcat(ds.B, {' and '}, ds.B);
> disp(ds)

I finally got around to checking your solution. It works perfectly without any warnings too. Still new to datasets so it was refreshing to actually have a correct answer for once. Thanks again James.

Date Subject Author
1/11/13 Kevin Ellis
1/11/13 james bejon
1/12/13 Kevin Ellis