Sorry for the long quote of Wikipedia on neutron decay, but I need to comment on all those features that Wikipedia talks about, for it shows the falsity of the Standard Model.
And one can see why I needed to talk about the three possible lines of Geometry, straight line, curved inward line and curved outward line for the Euclidean, Elliptic and Hyperbolic geometry.
This is important as to what to expect in neutron decay.
If you believe in the Standard Model, the neutron decays because of the proton alters a quark from being udd to that of being udu. So in Standard Model, the proton initiates the decay. In New Physics, the opposite is predicted. That the electron initiates the decay and that quarks are silly nonexistent contraptions by over imaginative physicists.
In New Physics, what initiates neutron decay of the free neutron is the fact that outside the atom nucleus, the neutron is in a Euclidean space geometry and the Maxwell Equations no longer holds the electron bound with the proton together. The electron in New Physics is hyperbolic geometry whereas the proton is elliptic geometry and the electron follows a hyperbolic path away from the proton.
So here we see two theories that diverge drastically, for the Standard Model predicts the proton as the initiator of the decay of free neutron, and the New Physics with the Maxwell Equations as axioms predicts the electron is the initiator of the neutron decay.
Now I said I was sorry for making such a long quote of Wikipedia, but you can see clearly why I did that because in that last paragraph Wikipedia mentions a small fraction of neutron decays where the electron stays stuck to the proton. So the importance of that last paragraph is that it contradicts the entire Quark theory based Standard Model by telling us, it is not the proton that starts the neutron to decay, but rather, the electron. And so that means the quark theory is worthless junk.
As a free neutron decays, it decays because the neutron is no longer confined by Maxwell Equations in the small tiny space of the nucleus of its 10^-16 meters. The confinement allows the electron inside the neutron to stay bound to the other protons of the nucleus. When outside the nucleus the neutron has its nuclear electron obey its Hyperbolic geometry and begins the process of the decay of the neutron.
So, here is a experimental prediction that separates the New Physics with its Maxwell Equations, separates it from the Old Physics of Standard Model with its quark nonsense.
Experiment: test to see which particle is first observed in a neutron decay-- is it the proton or is it the electron? If it is the proton, then there should not be any experiments showing the electron stayed stuck with the proton.
--- quoting Wikipedia on neutron decay --- Under the Standard Model of particle physics, because the neutron consists of three quarks, the only possible decay mode without a change of baryon number is for one of the quarks to change flavour via the weak interaction. The neutron consists of two down quarks with charge ?1?3 e and one up quark with charge +2?3 e, and the decay of one of the down quarks into a lighter up quark can be achieved by the emission of a W boson. By this means the neutron decays into a proton (which contains one down and two up quarks), an electron, and an electron antineutrino. Free neutron decay Outside the nucleus, free neutrons are unstable and have a mean lifetime of 881.5±1.5 s (about 14 minutes, 42 seconds); therefore the half-life for this process (which differs from the mean lifetime by a factor of ln(2) = 0.693) is 611.0±1.0 s (about 10 minutes, 11 seconds).  Free neutrons decay by emission of an electron and an electron antineutrino to become a proton, a process known as beta decay: n0 ? p+ + e? + ? e The decay energy for this process (based on the masses of neutrino, proton, and electron) is 0.782 343 MeV. The maximal energy of the beta decay electron (in the process wherein the neutrino receives vanishing kinetic energy) has been measured at 0.782 ± .013 MeV. The latter number is not well-enough measured to constrain the rest mass of the neutrino as well as it is constrained by many other methods. A small fraction (about one in 1000) of free neutrons decay with the same products, but add an extra particle in the form of an emitted gamma ray: n0 ? p+ + e? + ? e + ? This gamma ray may be thought of as a sort of "internal bremsstrahlung" which arises as the emitted beta particle interacts with the charge of the proton in an electromagnetic way. Internal bremsstrahlung gamma ray production is also a minor feature of beta decays of bound neutrons (as discussed below). Finally, a very small minority of neutron decays (about four per million) are so-called "two-body decays," in which the proton, electron and antineutrino are produced, but the electron fails to gain the 13.6 eV necessary energy to escape the proton, and therefore simply remains bound to it, as a neutral hydrogen atom. In this type of free neutron decay, essentially all of the neutron decay energy is carried off by the antineutrino. --- end quoting ---
-- Google's archives are top-heavy in hate-spew from search-engine- bombing. Only Drexel's Math Forum has done a excellent, simple and fair archiving of AP posts for the past 15 years as seen here: