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Re: simplifying rational expressions
Posted:
Jan 16, 2013 11:59 PM
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Thank you for the suggestion. I did try the equation after I solved
it based on input from several other kind souls in here. That site
did spit out the same answer. I will bookmark the site to check up on
my answers to see whether I did them right. Thank you.
s
On Wed, 16 Jan 2013 10:18:00 -0200, "JJAthayde" <jjathayde@uol.com.br>
wrote:
>
>"stony" <x@x.com> escreveu na mensagem
>news:uqfcf8dvhsqr7qjsdi09b8agcahbsr98ah@4ax.com...
>> Hi,
>> Need a little help with this. We are simplifying the following, but
>> the solution is pretty lengthy and messy because of the enormous
>> number of factors. I was thinking that may be I am missing seeing a
>> pattern (some series or something). Is grunt work the only way to
>> solve this or is there a pattern that can simplify the whole process?
>> My daughter was trying to solve this, but ended up with the mess and
>> then I got the same mess, but I thought there may be an easy way to
>> simplify this that I may be missing.
>> ((b-c)/((a-b)(a-c))) + ((c-a)/((b-c)(b-a))) + ((a-b)/((c-a)(c-b))) +
>> (2/(b-a)) - (2/(c-a))
>> of course, I took all the factors in the denominator and then started
>> multiplying the numerator with the remaining factors to end up with a
>> mess.
>> Your help is appreciated.
>> s
>
>Hi Stony.
>
> With the help of Google I've found this site:
>
>http://www.quickmath.com/webMathematica3/quickmath/algebra/factor/basic.jsp
>
> As I've seen, it works OnLine, so you'll get a solution immediately.
> I hope this will help you.
> Bye,
>
>
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