
testing out the Malus law replacement in Ohm's law of the Faraday law Chapt15.34 explaining Superconductivity from Maxwell Equations #1174 New Physics #1294 ATOM TOTALITY 5th ed
Posted:
Jan 23, 2013 1:05 PM


Testing out the Malus law replacement in Ohm's law of the Faraday law.
Now then, in my prior post I showed where Faraday's law is Ohm's law: In Faraday's law as stated by: emf = N dB/dt where 1/N is Resistance, and dB/dt is Voltage and emf is current i, and where we delete the negative sign.
So Faraday's law becomes:
i = V/R
Now for superconductivity, the R becomes another function of the Malus law I' = I" cos^2 A.
So we replace R in i = V/R with the Malus law
i = V/(I"cos^2A)
Now let us check out in an experiment whether that is what happens in physics.
On page 740 of Halliday & Resnick, Fundamentals of Physics, 3rd edition, 1988, shows experiment one of what is likely a remake of what Faraday did in the 1830s of his famous Faraday law. On page 740 shows a closed loop wire connected to a Galvanometer, G, and a hand holding a bar magnet aimed at moving into the center of the closed loop of wire and by the motion, the G should register a small electric current.
Now, to test out whether the Malus law is applicable, we redo that experiment and hold the bar magnet so that it does not move into the center at a perpendicular to the wire loop cross section area. We move the bar magnet at a oblique angle, just as in Malus law, we have a oblique polarized filter.
So, the question is, how does the current in G register with the bar magnet motion at oblique angles?

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