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testing out the Malus law replacement in Ohm's law of the Faraday law Chapt15.34 explaining Superconductivity from Maxwell Equations #1174 New Physics #1294 ATOM TOTALITY 5th ed
Posted:
Jan 23, 2013 1:05 PM
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Testing out the Malus law replacement in Ohm's law of the Faraday law.
Now then, in my prior post I showed where Faraday's law is Ohm's law: In Faraday's law as stated by: emf = -N dB/dt where 1/N is Resistance, and dB/dt is Voltage and emf is current i, and where we delete the negative sign.
So Faraday's law becomes:
i = V/R
Now for superconductivity, the R becomes another function of the Malus law I' = I" cos^2 A.
So we replace R in i = V/R with the Malus law
i = V/(I"cos^2A)
Now let us check out in an experiment whether that is what happens in physics.
On page 740 of Halliday & Resnick, Fundamentals of Physics, 3rd edition, 1988, shows experiment one of what is likely a remake of what Faraday did in the 1830s of his famous Faraday law. On page 740 shows a closed loop wire connected to a Galvanometer, G, and a hand holding a bar magnet aimed at moving into the center of the closed loop of wire and by the motion, the G should register a small electric current.
Now, to test out whether the Malus law is applicable, we re-do that experiment and hold the bar magnet so that it does not move into the center at a perpendicular to the wire loop cross section area. We move the bar magnet at a oblique angle, just as in Malus law, we have a oblique polarized filter.
So, the question is, how does the current in G register with the bar magnet motion at oblique angles?
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