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Re: Quicker way to rotate a 3 dimensional array?
Posted:
Jan 27, 2013 11:48 PM
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"Phil " <matlab@test.com> wrote in message <ke4thb$s7j$1@newscl01ah.mathworks.com>...
> I've got an array that is three dimensional where the first two dimensions are relatively large numbers and the third has length 3. This third one contains x,y,z co-ordinates that I would like to rotate about the x axis. I've managed to do this using:
>
> tmp3 = tmp;
> k = 0;
> for i=1:height
> for j=1:width
> k = k + 1;
> tmp3(i,j,:) = reshape(tmp(i,j,:),1,3)*[1,0,0;0,cos(theta),sin(theta);0,-sin(theta),cos(theta)];
> end
> end
>
> This works but as it's iterating, it's quite slow. Is there a faster way to do this?
- - - - - - - - - -
Assuming theta is a scalar try this:
tmp3 = tmp;
tmp3(:,:,2) = tmp(:,:,2)*cos(theta)-tmp(:,:,3)*sin(theta);
tmp3(:,:,3) = tmp(:,:,2)*sin(theta)-tmp(:,:,3)*cos(theta);
Roger Stafford
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