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A N Niel
Posts:
2,255
Registered:
12/7/04


Re: Another Limit Problem
Posted:
Jan 29, 2013 9:12 AM


In article <LbydnWRm6eYGV5rMnZ2dnUVZ_uKdnZ2d@earthlink.com>, Charles Hottel <chottel@earthlink.net> wrote:
> How can I find lim(x>0) tan 5x /sin 2 x ? > > I have tried manipulating this every way I can think of, but I still end up > with a fraction that contains a denominator of zero. Thanks. > >
Can you do lim(x>0) (sin x)/x ? If so, think of how that may be relevant to your problem.



