JT
Posts:
1,386
Registered:
4/7/12


Re: 1/3 partitioned expansion in different bases
Posted:
Feb 1, 2013 11:40 PM


On 2 Feb, 03:54, forbisga...@gmail.com wrote: > On Friday, February 1, 2013 1:10:12 PM UTC8, JT wrote: > > You are confused the zeros in 1/2 1/4 etc etc is imaginary not real. > > And for the endless expansion of digits in 1/3, 1/7 i offered a > > solution using bases without zero. > > And what of x in > x = 1  1 Well what i try to say with all this is that the empty set do not need a placholder, so =yy as you can see there is no reminants of y it is completly depleted. > Now construct 1/9th in base 3.
Well i have not thought it thru for empty positions in the digit expansion but i guess it will end up be. 1/3=,1 1/9=,(2)1 1/27=,(3)1
2/3=,2 2/9=(2)2 2/27=(3)2
And so on, well you get the hang of it although i am not finished thinking it thru for fractional digit places, i think i can do all this for all bases with just 3 or 4 lines of codes, and it will of course translate back to standard decimal base within that code.
> > 0.[9] in base 10(given 9 is followed by 10) > 0.[2] in base 3 is the same. > > x = 0.[2] I am not sure i understand your notation does it say x=0,2? > 10x = 2.[2] How can then 10x be 2,2? > 10x  x = 2 This i follow > 2x = 2 This follow > x = 1 But what do you want to say or ask with this?
> I can disagree with Frederik Williams about > .3 base 3 = 1 base 3 in your numbering system > Now what was the benefit again? Why do I want a > 3 in base 3?

