If (Y,d) is complete, then Y is closed with respect to d. That is,
Alternatively, if (Y,d) is complete, then Y contains all its limit points.
Would anyone happen to know of a counterexample for the converse? That is, does someone know of any example that demonstrates that closed --> complete is *not* true? I don't know for sure that it is not true, but I might guess that it is not true.