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Topic: Re: Using NDSolve solution as an initial condition for another
Replies: 0

 Alexei Boulbitch Posts: 483 Registered: 2/28/08
Re: Using NDSolve solution as an initial condition for another
Posted: Feb 2, 2013 1:15 AM

Hi,

I have a PDE that I've solved numerically, but now I need to use that solution as an initial condition for another PDE. Is there a way I can do this?

Thank you,
Teresa

Hi, Teresa,

It seems to be rather straightforward. The only question is that you need to take care of the boundary conditions of the second equation that in general may be in conflict with the solution of the first equation.
If this represents no problem in your case, you may do as I did below. I took two equation from the Examples Section of the Menu/Help/NDSolve:

This is the solution of the first equation for the function u=u(t,x):

s = NDSolve[{D[u[t, x], t] == D[u[t, x], x, x] + Cos[x - t],
u[0, x] == Sin[2 \[Pi]*x/5], u[t, 0] == 0, u[t, 5] == 0},
u, {t, 0, 2 \[Pi]}, {x, 0, 5}][[1, 1]]

Evaluate it and have a look here:

Plot3D[Evaluate[u[t, x] /. s], {t, 0, 2 \[Pi]}, {x, 0, 5},
PlotRange -> All]

The second equation is for the function v=v(t,x). Its initial condition is

v[0,x]==u[10, x] /. s

This is the plot of the initial condition for the second equation:

Plot[Evaluate[u[2 \[Pi], x] /. s], {x, 0, 5}]

The solution takes the following form:

ss = NDSolve[{\!\(
\*SubscriptBox[\(\[PartialD]\), \(\[Tau]\)]\(v[\[Tau], x]\)\) == \!\(
\*SubscriptBox[\(\[PartialD]\), \(x, x\)]\(v[\[Tau], x]\)\),
v[0, x] == Evaluate[u[2 \[Pi], x] /. s], v[\[Tau], 0] == 0,
v[\[Tau], 5] == 0}, v, {\[Tau], 0, 10}, {x, 0, 5}]

Have a look at the solution here:

Plot3D[Evaluate[v[t, x] /. ss], {t, 0, 10}, {x, 0, 5},
PlotRange -> All]

Have fun, Alexei

Alexei BOULBITCH, Dr., habil.
IEE S.A.
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