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JT
Posts:
432
Registered:
4/7/12
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Re: JS coding
Posted:
Feb 24, 2013 6:17 AM
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On 23 Feb, 14:43, JT <jonas.thornv...@gmail.com> wrote: > On 23 Feb, 08:46, Virgil <vir...@ligriv.com> wrote: > > > > > > > > > > > In article > > <414addb8-8932-4800-b866-c5032e800...@g16g2000vbf.googlegroups.com>, > > > JT <jonas.thornv...@gmail.com> wrote: > > > On 11 Feb, 00:17, Virgil <vir...@ligriv.com> wrote: > > > > In article > > > > <61208bd6-9348-44cd-98e6-14e4c7681...@hl5g2000vbb.googlegroups.com>, > > > > > JT<jonas.thornv...@gmail.com> wrote: > > > > > Below ternary fractions in NyaN > > > > > Paragraphs for empty preceding > > > > > entrys to keep track of multiple * bas (Ternary=1,3,9,27,81....) > > > > > > Fractions = NyaN ternary fraction > > > > > 1/3 = .1 > > > > > 2/3 = .2 > > > > > 1/9 = .(1)1 > > > > > 2/9 = .(1)2 > > > > > 1/27 = .(2)1 > > > > > 2/27 = .(2)2 > > > > > 1/81 = .(3)1 > > > > > 2/81 = .(3)2 ... > > > > > Since 0's in standard notation are merely placeholders, you still > > > > apparently need placeholders. > > > > > HOW IS 1/81 = .(3)3 BETTER THAN 1/81 =.0001 in base 3? > > > > -- > > > > No there is no placeholders needed for the naturals because they are > > > discrete incremental entities > > > In decimal notation, 10 and 100 and 1000, and so forth all require > > placeholders.
It is not the partitioning/grouping into bases itself that are in question, what is in question if we really should allow write empty positions in bases.
Example 21 decimal equals 210 in ternary (2*9)+(1*3)+(0*1) while in NyaN numbers represented in bases do not have void positions =(0), so using NyaN writing 21 in ternary equals 133 (1*9)+(3*3)+(1*3) this way to write numbers is of course working for anybase so ternary 1000000000000000000100000000000000000001/201 would be much easier perform using NyaN
> No they do not need ask the romans they used X, but for us maybe A > would be more suitable. > Now you have 123456789A or 123456789X instead of 0123456789 you may > notice the zero is gone. > > zero is just a distraction performing math, especially when dividing > writing without zeros have great computational advantages when it come > to factoring, it may also come with some insight into prime number > distribution so finally someone can crack the mystery of the Riemann > zeta function. > > > > > > > > > > \ the fractions though are parts of the > > > continuum and expressed as part of one whole. This does not mean there > > > is really any numerical value to the preceding zeros as you as well > > > could write it as 10^-3 or A^-3. > > > And how is writing 5*10^-3 any less placeholder dependent that 0.005? > > > In one way or another, the existenceof places holding 0's must be noted. > > --
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