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Re: Finite Rings
Posted:
Feb 4, 2013 12:42 PM
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On Monday, February 4, 2013 11:12:42 AM UTC-6, quasi wrote:
> >> x^2 = x, y^2 = x, z^2 = x
[...]
> > No -- you misread some of my specified conditions. > > > > Look more carefully at how I defined the products > > x^2, y^2, z^2.
Quite right; sorry about that.
But now note: x(yy) = xx = x; but (xy)y = 0y = 0. So you don't have an associative ring.
-- Arturo Magidin
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