quasi
Posts:
10,566
Registered:
7/15/05


Re: Finite Rings
Posted:
Feb 4, 2013 12:55 PM


Arturo Magidin wrote: >quasi wrote: >> >> >> >> x^2 = x, y^2 = x, z^2 = x > > [...] > >> >> No  you misread some of my specified conditions. >> >> Look more carefully at how I defined the products >> >> x^2, y^2, z^2. > >Quite right; sorry about that. > >But now note: >x(yy) = xx = x; but (xy)y = 0y = 0. >So you don't have an associative ring.
Ouch!
It never occurred to me that I'd lost associativity.
That pretty much destroys my attempted counterexample.
Oh well.
Thanks for the identifying the issue.
quasi

