Drexel dragonThe Math ForumDonate to the Math Forum



Search All of the Math Forum:

Views expressed in these public forums are not endorsed by Drexel University or The Math Forum.


Math Forum » Discussions » sci.math.* » sci.math.independent

Topic: A quicker way?
Replies: 8   Last Post: Feb 4, 2013 1:44 PM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
quasi

Posts: 9,921
Registered: 7/15/05
Re: A quicker way?
Posted: Feb 4, 2013 10:27 AM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

luttgma@gmail.com wrote:

>Let n^2 = N + a^2, where n, N and a are integers.
>Knowing N, it is of course possible to find n by trying
> a = 1, 2, 3, 4, etc...
>But doesn't exist a quicker way ?


if you rewrite the equation in the form

(n - a)(n + a) = N

then for each pair of integers u,v with u*v = N, you can
solve the equations

n - a = u
n + a = v

for n and a.

quasi



Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© Drexel University 1994-2014. All Rights Reserved.
The Math Forum is a research and educational enterprise of the Drexel University School of Education.