Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
Drexel University or The Math Forum.



Re: Kronecker product reversal, or division
Posted:
Feb 7, 2013 5:34 PM


On Feb 7, 12:54 pm, carolinebal...@gmail.com wrote: > I have a Kronecker product (A) of an unknown (B) and a known (A) matrix: A = B ? C. Again, A and C are known  I wish to calculate B. Incidentally, C is an identity matrix times a known constant. > > Is it possible to recover B? > > If so, does anyone have a bit of code to do this? (I write in IDL.) > > Thanks, > Caroline
If B is 4 x 2 and C is 3 x 3 then A should look like this:
b11*c 0 0 b12*c 0 0 0 b11*c 0 0 b12*c 0 0 0 b11*c 0 0 b12*c b21*c 0 0 b22*c 0 0 0 b21*c 0 0 b22*c 0 0 0 b21*c 0 0 b22*c b31*c 0 0 b32*c 0 0 0 b31*c 0 0 b32*c 0 0 0 b31*c 0 0 b32*c b41*c 0 0 b42*c 0 0 0 b41*c 0 0 b42*c 0 0 0 b41*c 0 0 b42*c
Just divide by c. You should get 3 copies of each element of B.



