On Feb 13, 11:33 pm, David Waite wrote: > On Wednesday, February 13, 2013, Koobee Wublee wrote:
> > Have you really derived the field equations in their > > useful form in differential equations? It is very certain > > you have not. If you do, why don?t you post the null > > Einstein tensor in polar coordinate (diagonal metric)? <shrug> > > > All the solutions you have pulled out of your ass do not > > satisfy the Einstein field equations. You are just shooting > > in the dark with no fvcking idea of what you are doing. <shrug> > > ok: > > > grtw(); > > GRTensorII Version 1.79 (R6) > > 6 February 2001 > > Developed by Peter Musgrave, Denis Pollney and Kayll Lake > > Copyright 1994-2001 by the authors. > > Latest version available from:http://grtensor.phy.queensu.ca/
Who has validated this software? <shrug>
Eric Gisse the college dropout possessed software that gives the following as the solutions to the null Einstein tensor (or Ricci tensor).
** ds^2 = c^2 dt^2 / (1 + K / r) ? (1 + K / r) dr^2 ? r^2 (1 + K / r)^2 dO^2
** U = G M / c^2 / r
The spacetime geometry satisfies the general form below where [R(r) = r].
** ds^2 = c^2 dt^2 / (1 + K / R) ? (1 + K / R) (dR/dr)^2 dr^2 ? R^2 (1 + K / R)^2 dO^2
The above spacetime geometry satisfies the null Einstein or Ricci tensor with diagonal metric in polar coordinate system. For example, when [R(r) = r - K], the result is the Schwarzschild metric. What should R be to get to your metric? None. Thus, you are wrong. You have relied on others to give you solutions which you have no way of verifying. <shrug>
If you want, Koobee Wublee can give you the null Einstein tensor with diagonal metric in polar coordinate system where you can test out your metric. <shrug>