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Topic: Electrodynamics in general relativity
Replies: 4   Last Post: Feb 14, 2013 1:54 PM

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Koobee Wublee

Posts: 1,417
Registered: 2/21/06
Re: Electrodynamics in general relativity
Posted: Feb 14, 2013 12:29 PM
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On Feb 13, 11:33 pm, David Waite wrote:
> On Wednesday, February 13, 2013, Koobee Wublee wrote:

> > Have you really derived the field equations in their
> > useful form in differential equations? It is very certain
> > you have not. If you do, why don?t you post the null
> > Einstein tensor in polar coordinate (diagonal metric)? <shrug>

>
> > All the solutions you have pulled out of your ass do not
> > satisfy the Einstein field equations. You are just shooting
> > in the dark with no fvcking idea of what you are doing. <shrug>

>
> ok:
>

> > grtw();
>
> GRTensorII Version 1.79 (R6)
>
> 6 February 2001
>
> Developed by Peter Musgrave, Denis Pollney and Kayll Lake
>
> Copyright 1994-2001 by the authors.
>
> Latest version available from:http://grtensor.phy.queensu.ca/


Who has validated this software? <shrug>

Eric Gisse the college dropout possessed software that gives the
following as the solutions to the null Einstein tensor (or Ricci
tensor).

** ds^2 = c^2 dt^2 / (1 + K / r) ? (1 + K / r) dr^2
? r^2 (1 + K / r)^2 dO^2

Where

** U = G M / c^2 / r

The spacetime geometry satisfies the general form below where [R(r) =
r].

** ds^2 = c^2 dt^2 / (1 + K / R) ? (1 + K / R) (dR/dr)^2 dr^2
? R^2 (1 + K / R)^2 dO^2

The above spacetime geometry satisfies the null Einstein or Ricci
tensor with diagonal metric in polar coordinate system. For example,
when [R(r) = r - K], the result is the Schwarzschild metric. What
should R be to get to your metric? None. Thus, you are wrong. You
have relied on others to give you solutions which you have no way of
verifying. <shrug>

If you want, Koobee Wublee can give you the null Einstein tensor with
diagonal metric in polar coordinate system where you can test out your
metric. <shrug>





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