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Topic: How to get the FFT cycles: N>8 Tcycle = 3N/2-2 + log2(N)*(N/2+3);
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fl

Posts: 80
Registered: 10/8/05
How to get the FFT cycles: N>8 Tcycle = 3N/2-2 + log2(N)*(N/2+3);
Posted: Feb 26, 2013 10:35 AM
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Hi,
I use Simulink FFT block to generate HDL code. The help says:

N>8 Tcycle = 3N/2-2 + log2(N)*(N/2+3);

I see that it uses 4 multipliers in the butterfly. I would like to know the meaning of the above equation. 3N/2-2 is the prelog?

For each cyle, what is the cycle number? It uses 4 DPRAM. I guess that it should have a number account for the DPRAM cycles, some delay register cycles, but I cannot find that number in the above eqaution. Could you help me?

Thanks,



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