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Topic: pde toolbox
Replies: 13   Last Post: Apr 23, 2013 4:29 PM

 Messages: [ Previous | Next ]
 srao Rao Posts: 29 Registered: 7/16/10
Re: pde toolbox
Posted: Mar 25, 2013 2:06 PM

"Bill Greene" wrote in message <ki2os3\$gna\$1@newscl01ah.mathworks.com>...
> "Sashankh Rao" wrote in message <ki291f\$56f\$1@newscl01ah.mathworks.com>...
>

> > I then mesh it: [p,e,t] = initmesh(g);
> > Then I create my boundary matrix using [Q,G,H,R] = pdebound(p2,e2);
> > I then assemble other matrices using [K,M,F] = assema(p,t,c,a,f);
> > Finally I solve the problem using u = assempde(K,M,F,Q,G,H,R);

>
>
> Ah, I see that the documentation page I pointed you to doesn't
> show you what to do with the pdebound function once you've created it--
> sorry.
>
> That function is actually called by the PDE Toolbox routines-- not by you.
> If you don't want to do anything fancy, but simply want a solution, do this:
>
> b=@pdebound; % the "pdebound" function can have any name
> % also define p,e,t,c,a,f
> u=assempde(b,p,e,t,c,a,f);
>
> Regards,
>
> Bill

> > ------------------------------------------
> > As per the link below the size of the Q matrix in the boundary file is (N^2 ne) which for a one-dimensional system is (1 ne), where ne is the number of edges in the mesh.
> >
> > http://www.mathworks.com/help/pde/ug/boundary-conditions-for-scalar-pde.html
> >
> > However the size for the K and M matrices is (Np Np) where Np is the number of nodes in the matrix.
> >
> > So I see that the K matrix and Q matrix are not of the same dimensions and hence the error. I am not able to figure out how to fix this problem. Any help will be appreciated very much.
> >
> > Thank you.
> >
> > "Bill Greene" wrote in message <khfgev\$sgb\$1@newscl01ah.mathworks.com>...

> > > Hi,
> > >
> > > "Sashankh Rao" wrote in message <khdu9o\$j3c\$1@newscl01ah.mathworks.com>...

> > > > Using the Matlab pde toolbox I obtain a solution to the Poisson equation for a given geometry using dirichlet boundary conditions. First, I want to determine the gradient at all the boundary nodes. Is this possible using the toolbox? Second, I want to use these gradient values as an input boundary condition for the same boundary to solve a different equation (same geometry). Is this possible to do using the toolbox? Thanks.
> > >
> > > Yes, this is definitely possible. I'll try to point you in the right direction.
> > >
> > > The function pdegrad can be used to calculate the gradient of the solution at the
> > > element centroids.
> > > Then the function pdeprtni can be used to interpolate these centroid values back
> > > to the nodes.
> > > http://www.mathworks.com/help/pde/ug/pdeprtni.html
> > >
> > > Using these gradient values in the boundary conditions will require you to write your
> > > own boundary condition function, referred to as a "boundary file" in the PDE
> > > Toolbox documentation.
> > > http://www.mathworks.com/help/pde/ug/pdebound.html
> > >
> > > This documentation page has some examples of how to write such a function.
> > > http://www.mathworks.com/help/pde/ug/boundary-conditions-for-scalar-pde.html
> > >
> > > Bill

Hi Bill,

I have another question related to the above thread.

I am trying to impose the Neumann condition at nodes on the boundary. To do this I need to pass additional information to pdebound as shown below.

function [qmatrix,gmatrix,hmatrix,rmatrix] = pdebound2(p,e,u,time,u2bn,loc)

where u2bn and loc are the additional data. However, I get the following error in trying to do so:

Input argument "u2bn" is undefined.
Error in ==> pdebound2 at 13

Looks like pdebound will not accept additional data. I am using

b = @pdebound;

to assemble my boundary matrix.

Thanks for taking time to help me. Really appreciate it.

Sashankh

Date Subject Author
3/8/13 srao Rao
3/9/13 Bill Greene
3/11/13 srao Rao
3/16/13 srao Rao
3/16/13 Bill Greene
3/17/13 srao Rao
3/25/13 srao Rao
3/25/13 srao Rao
3/28/13 Alan Weiss
4/22/13 srao Rao
4/23/13 Alan Weiss
4/23/13 srao Rao
4/23/13 Bill Greene
4/23/13 srao Rao