The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » sci.math.* » sci.math

Topic: How to calculate bevel angles for cutting combined compound angles?
Replies: 4   Last Post: Mar 12, 2013 8:16 PM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
James Waldby

Posts: 506
Registered: 1/27/11
Re: How to calculate bevel angles for cutting combined compound

Posted: Mar 10, 2013 2:55 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

On Sun, 10 Mar 2013 10:09:02 -0700, Christoph J. WALTHER wrote:

> With a miter saw I want to cut the end of a beam (fig. 1 in the sketch I posted here: ) so that two miter cuts (arrow heads, fig. 3) at 54.4° result at their intersection in a given angle (base angle, fig. 2 and fig. 4) of 10.3° in my example (for a more visual description one might check this video here: where, however, it gets omitted to mention that bevel angle need to be applied). I did a test cut with setting the bevel angle at 5°, tilting right and left respectively for each of the cuts, what resulted in a base angle of approx. 8°. So the approach seems to be correct, but I need to be able to control it and hence I need help in calculating the bevel angle to set at the miter saw when cutting the two miter angles. Any help, even hints pointing into the right direction, is greatly appreciated! TIA!!!

For a board that is s units high, the heel of the cut (in Figure 2) is set
in by a distance x = s sin(b), where b is your 10.3° (10.3 degrees) angle.
Let a=54.4°. If your board is sitting on a horizontal plane T and you
drop a vertical line segment of length s from the corner near the lower
54.4° label in Figure 3, it will impinge T at a point P a distance x from
the heel. On T we can draw a right triangle with side x cos(a), angle a,
hypotenuse x, and side u = x sin(a). The first side mentioned is part of
an arrow line on T, and would be like in Figure 3 but with the arrow lines
translated distance x to the right. Anyhow, we have a right triangle with
side s next to the bevel angle and side u opposite the bevel angle, which
gives bevel angle m = arctan(u/s).

The following Python 2 code computes m = 8.27° with s=3.5 and a, b as above:

from math import sin, pi, atan2
def d2r(d): return d*pi/180
s, a, b = 3.5, 54.4, 10.3
x = s * sin(d2r(b)); print x
u = x * sin(d2r(a)); print u
m = atan2(u, s); print m*180/pi

The above code prints out:

which indicates that the heel inset is about 5/8" and the bevel angle 8.27°

Question: Why is your main angle 54.4° instead of 54° ? It appears that
54.4° gives you an arrow angle of 180-2*54.4 = 71.2° instead of a proper
pentagon angle of 72°.


Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2017. All Rights Reserved.