waku
Posts:
14
Registered:
1/27/11


Re: Noob requests help with recursive formula
Posted:
Mar 14, 2013 7:12 AM


On 03/13/2013 09:19 AM, Garcia5529@yahoo.fr wrote: > I appreciate any tips on how to code this in Mathematica. > I have two lists, each with 99 elements; A and B. Real numbers. > I want to form a list, C, whose elements are functions (F[]) of A and B, and also previous elements of C itself. > > C ={F[A1/B1], F[A2/(B2A1/C1)], F[A3/(B3A1/C1A2/C2)],..F[A99/(B99A1/C1...A98/C98.)} > > ...where the integers after A,B, and C, are element indices. > Thanks for any suggestions. > HG >
As far as I understand your request, here is one, not necessarily optimal way of solving your problem:
whatever[as_,bs_,cs_] := MapThread[f[#1/(#2#3)]&, {as, bs, Prepend[Most@Accumulate[as/cs], 0]}]
Tested on dummy data:
whatever @@ Table[Table[Subscript[v, i], {i, 99}], {v, {a, b, c}}]
vQ

