Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
Drexel University or The Math Forum.
|
|
|
|
Re: How to take mean in 3rd dimension of matrix within a loop
Posted:
Mar 15, 2013 3:08 PM
|
|
"Max " <nizabat@gmail.com> wrote in message
news:khvah3$7ov$1@newscl01ah.mathworks.com...
> Dears,
> I want to take average of long data array in 3rd dimension, but I am not
> getting the wanted result. Lets say I have A = rand(8,8,10); Now
> averaging (mean) over let say each 2 values in 3rd dimension, it should
> give me size 8x8x5.
> I did this, but doesn't work
> A1 = [];
> for m = 1: 2: 10
> A1 = [A1; mean(A(:,:,m:m+1),3)];
> end
>
> Any help in this regard would highly appreciated. Thanks
B = (A(:, :, 1:2:end) + A(:, :, 2:2:end)) / 2;
or if you want to avoid the ENDs for some reason:
nPages = size(A, 3);
B = (A(:, :, 1:2:nPages) + A(:, :, 2:2:nPages)) / 2;
Note that if A is 4-or-higher dimensional this will do something you may not
expect. See example 2 on this page:
http://www.mathworks.com/help/matlab/ref/size.html
--
Steve Lord
slord@mathworks.com
To contact Technical Support use the Contact Us link on
http://www.mathworks.com
|
|
|
|
