
Re: Complex Circular (Coci) and Complex Hyperbolic (Cohy) Numbers
Posted:
Mar 31, 2013 2:56 AM


> From: Doctor Nisith Bairagi > Subject: Complex Circular (Coci) and Complex > Hyperbolic (Cohy) Numbers > Date: March 30, 2013 > (sci.math.independent) > >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> > Dear Readers, > Please comment on the new proposal for representing > the complex numbers. Your constructive criticism on > this topic will be an asset. > >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> > > A complex number [a (+/) ib], can be represented > through several ways, viz., > Complex Circular (Coci) form, and Complex Hyperbolic > form, and accordingly, the number may be identified > as Coci number or Cohy number. While the Coci form is > well known, the Cohy form, is presented as a new > proposal. > > Coci number: > Using exponential function, e^c = (cosh c + sinh x), > we write: > Coci number: a (+/) ib = R [cos c (+/) i sin c] = R > [e^ (+/)(ic)], > (a, b) = R(cos c, sin c), tan c = b/a, > R = sqrt[a^2 + b^2], R is + ve, irrespective of a>b, > or b>a. > > Cohy number: > Creating fexponential function, f^x = (cos x + sin > x), we write: > Cohy number: a (+/) ib = H [cosh x (+/) i sinh x] = > H [f^ (+/)(ix)], > (a, b) = H (cosh x, sinh x), tanh x = b/a, > H = sqrt[a^2b^2], H is + ve, if a>b, but if b>a, H > is complex, say = (iH), (here, H = mod value of H). > > Interchangeability of Coci and Cohy parameters: > a^2 + b^2 = R^2 [(cos c)^2 + (sin c)^2] = H^2 [(cosh > x)^2 + (sinh x)^2], > so, R = H sqrt[cosh(2x)]. > a^2b^2 = R^2 [(cos c)^2(sin c)^2] = H^2 [(cosh > x)^2(sinh x)^2], > so, R sqrt[cos(2c)] = H. > From these two, get: cos(2c).cosh(2x) = 1. > Alternative forms are: sin(2c) = tanh(2x), and, > tan(2c) = sinh(2x). > > For Cohy numbers, special attaintion is drawn, if > a<b: > Note that, H is complex, so replace H by (iH), and > multiply both sides by (i). > a + ib = (iH) [cosh x + i sinh x]. > (i)(a + ib) = (i)(iH) [cosh x + i sinh x]. > bia = H[cosh x + i sinh x]. > > Note that since, cosh() = (+)ve, sinh() = ()ve, > then write, (b, a) = H[cosh(x), sinh(x)] > > [The complex number now is, as if (bia), and since > b>a, the rest of the procedure will follow for the > previous case as that for a>b.] > > Example1. Write (8 + 15i) in Coci and Cohy form. > (a, b) = (8, 15), a<b, > (8 + 15i) = R(cos c + sin c) = H(cosh x + sinh x), > R = sqrt[(8^2 + 15^2] = 17, > (cos c, sin c) = (8/17, 15/17), c = 61.9275 deg > (=1.0808 rad). > H = sqrt[(8^215^2] = 12.6886i (it is complex), /mod > H/ = 12.6886. > So, (bia) = (158i) = H[cosh x + i sinh x], > 12.6886 (cosh x, sinh x) = (15, 8), x = 0.5948. > [Taken that, cosh() = (+)ve, sinh() = ()ve] > > Thus, the Coci and Cohy forms of (8 + 15i), are: > (8 + 15i) = 17e^(1.0808i) = 12.6886f^(0.5948i) > > Check with: tan(2c) = sinh(2x) > sinh(2x) = tan(2c) = 1.49068, 2x = 1.18958, x = > 0.5948. > > Example2. (for a>b), > (12 + 5i) = 13e^(0.3948i) = 10.9087f^(0.4436i) > (125i) = 13e^(0.3948i) = 10.9087f^(0.4436i) > > Complex numbers of other forms: > The representation of complex numbers is not > restricted to Coci and Cohy varieties, but can be > extended to other forms. For example: like the pair > (cosh x, sinh x) of hyperbolic functions, pairs of > trigonometric (= circular) functions like, (sec u, > tan u), (cosec v, cot v) can also be utilized. The > method shown for Cohy numbers, will be applicable in > these cases, since, [(sec u)^2(tan u)^2] = 1, and, > [(cosec v)^2(cot v)^2] = 1. > > For, (a + ib) = S[sec u + i tan u] = C[cosec v + i > cot v], the interchangeability of the parameters are: > > (cos 2c).[1 + 2 (tan u)^2] = 1, and, tan c = sin u = > cos v > ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, > ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, > ,,,,,,,,,,,,,,,,,, > Thanks to All. > > Doctor Nisith Bairagi > Uttarpara, West Bengal, India > >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> > >>>>>>
From: Doctor Nisith Bairagi Subject: Complex Circular (Coci) and Complex Hyperbolic (Cohy) Numbers Date: March 30, 2013 (sci.math.independent) >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> NOTE: Corrected line shown on Example1 of the same Topic Posted on March 30, 2013, (where, i, was absent in two places)as: (8 + 15i) = R(cos c + i sin c)= H(cosh x + i sinh x) >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Dear Readers, Please comment on the new proposal for representing the complex numbers. Your constructive criticism on this topic will be an asset. >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
A complex number [a (+/) ib], can be represented through several ways, viz., Complex Circular (Coci) form, and Complex Hyperbolic form, and accordingly, the number may be identified as Coci number or Cohy number. While the Coci form is well known, the Cohy form, is presented as a new proposal. Coci number: Using exponential function, e^c = (cosh c + sinh x), we write: Coci number: a (+/) ib = R [cos c (+/) i sin c] = R [e^ (+/)(ic)], (a, b) = R(cos c, sin c), tan c = b/a, R = sqrt[a^2 + b^2], R is + ve, irrespective of a>b, or b>a.
Cohy number: Creating fexponential function, f^x = (cos x + sin x), we write: Cohy number: a (+/) ib = H [cosh x (+/) i sinh x] = H [f^ (+/)(ix)], (a, b) = H (cosh x, sinh x), tanh x = b/a, H = sqrt[a^2b^2], H is + ve, if a>b, but if b>a, H is complex, say = (iH), (here, H = mod value of H).
Interchangeability of Coci and Cohy parameters: a^2 + b^2 = R^2 [(cos c)^2 + (sin c)^2] = H^2 [(cosh x)^2 + (sinh x)^2], so, R = H sqrt[cosh(2x)]. a^2b^2 = R^2 [(cos c)^2(sin c)^2] = H^2 [(cosh x)^2(sinh x)^2], so, R sqrt[cos(2c)] = H. From these two, get: cos(2c).cosh(2x) = 1. Alternative forms are: sin(2c) = tanh(2x), and, tan(2c) = sinh(2x).
For Cohy numbers, special attaintion is drawn, if a<b: Note that, H is complex, so replace H by (iH), and multiply both sides by (i). a + ib = (iH) [cosh x + i sinh x]. (i)(a + ib) = (i)(iH) [cosh x + i sinh x]. bia = H[cosh x + i sinh x].
Note that since, cosh() = (+)ve, sinh() = ()ve, then write, (b, a) = H[cosh(x), sinh(x)]
[The complex number now is, as if (bia), and since b>a, the rest of the procedure will follow for the previous case as that for a>b.]
Example1. Write (8 + 15i) in Coci and Cohy form. (a, b) = (8, 15), a<b, (8 + 15i) = R(cos c + i sin c) = H(cosh x + i sinh x), R = sqrt[(8^2 + 15^2] = 17, (cos c, sin c) = (8/17, 15/17), c = 61.9275 deg (=1.0808 rad). H = sqrt[(8^215^2] = 12.6886i (it is complex), /mod H/ = 12.6886. So, (bia) = (158i) = H[cosh x + i sinh x], 12.6886 (cosh x, sinh x) = (15, 8), x = 0.5948. [Taken that, cosh() = (+)ve, sinh() = ()ve]
Thus, the Coci and Cohy forms of (8 + 15i), are: (8 + 15i) = 17e^(1.0808i) = 12.6886f^(0.5948i)
Check with: tan(2c) = sinh(2x) sinh(2x) = tan(2c) = 1.49068, 2x = 1.18958, x = 0.5948.
Example2. (for a>b), (12 + 5i) = 13e^(0.3948i) = 10.9087f^(0.4436i) (125i) = 13e^(0.3948i) = 10.9087f^(0.4436i)
Complex numbers of other forms: The representation of complex numbers is not restricted to Coci and Cohy varieties, but can be extended to other forms. For example, like the pair (cosh x, sinh x) of hyperbolic functions, pairs of trigonometric (= circular) functions like, (sec u, tan u), (cosec v, cot v) can also be utilized. The method shown for Cohy numbers, will be applicable in these cases, since, [(sec u)^2(tan u)^2] = 1, and, [(cosec v)^2(cot v)^2] = 1.
For, (a + ib) = S[sec u + i tan u] = C[cosec v + i cot v], the interchangeability of the parameters are: (cos 2c).[1 + 2 (tan u)^2] = 1, and, tan c = sin u = cos v ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, Thanks to All.
Doctor Nisith Bairagi Uttarpara, West Bengal, India >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>

