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Topic: "Programming With Mathematica" Exercise help
Replies: 10   Last Post: Apr 13, 2013 8:36 PM

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Posts: 7
Registered: 4/11/13
Re: "Programming With Mathematica" Exercise help
Posted: Apr 13, 2013 8:36 PM
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> Hold[z + 3] /. HoldPattern[z] -> a
> % // ReleaseHold

I would have thought this was the closest to what I would have called a "correct" answer since it actually uses hold and all the variables have their assigned values when the replacement takes place. I really think the most elegant way of doing it is the Unevaluated answer and the one that uses Block but neither uses Hold. Thanks - I guess HoldPattern is probably the magic I was looking for.

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