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Topic: Function preceding order within a deployed application
Replies: 2   Last Post: Apr 30, 2013 7:19 AM

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Bruno Luong

Posts: 9,822
Registered: 7/26/08
Function preceding order within a deployed application
Posted: Apr 24, 2013 6:46 AM
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I would like to know if the following specification

is applied for deployed code (using MATLAB compiler) as well?

On my test, the "Functions in the current folder" does not seem to shadow the hononyme function(s) for deployed application.

I would like to find a mechanism of shadowing function (as with non-deployed matlab) for deployed application, which works well under the compiler 2006B.

I don't find any relevant doc on the subject, beside Loren's blog (not quite a official reference spec to me).

Here is a minima example code, which comprises 3 files ./foo.m, ./subfolder1/subfun.m and ./subfolder2/subfun.m

function foo(varargin)
% function foo(varargin)
% mcc -C -m foo.m -a subfolder1/subfun.m -a subfolder2/subfun.m
% Minima example to illustrate the 'Function preceding order' document
% is not applicable in deployed code (2013A)

%% First path
path1 = locpath('subfolder1');
rehash path;
fun1 = @subfun;
fun = functions(fun1);

%% Second path
path2 = locpath('subfolder2');
rehash path;
fun2 = @subfun;
fun = functions(fun2);


input('foo>> Type CR to quit: ', 's' );

end % foo

function path = locpath(relpath)
% local function declared and used by in foo.m
% return the absolute path from the relative path
if isdeployed()
root = ctfroot();
root = fileparts(mfilename('fullpath'));
path = [root filesep() relpath];
end % locpath

function subfun( )
% subfun( )
% A dummy function located in subfolder1/subfun
fprintf('subfun in folder 1 call\n');
end % subfun

function subfun( )
% subfun( )
% A dummy function located in subfolder2/subfun
fprintf('subfun in folder 2 call\n');
end % subfun

If I run under MATLAB, I get this output:

>> foo
subfun in folder 1 call
subfun in folder 2 call

When running wth stand alone deployed application I get this.

C:\Somewhere> foo.exe

subfun in folder 2 call
subfun in folder 2 call

There is no way to shadow subfun in subfolder2. Is there any work around?


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