Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Topic: FINAL SPECIFIC CALCULUS OF PRIME NUMBER AS SHOWN HERE POSTED WITH
CAMBRIDGE JOURNALS AND JOHN HOPKINS MATHEMATICS JOURNALS

Replies: 2   Last Post: May 7, 2013 11:27 PM

 Messages: [ Previous | Next ]
 HOPEINCHRIST Posts: 342 From: USA Registered: 2/7/11
FINAL SPECIFIC CALCULUS OF PRIME NUMBER AS SHOWN HERE POSTED WITH
CAMBRIDGE JOURNALS AND JOHN HOPKINS MATHEMATICS JOURNALS

Posted: May 7, 2013 11:42 AM

This calculus is submitted to the best Mathematics brains in the World , Cambridge Journals , John Hopkins Journals, Its basic condition is mathematically solvable. Half-line value at 18 runs tandem with prime numbers thus allowing all calibrations. Please try and understand it first before blurting, as is the method of current mathematics, specially your Sci- math research. Prime number is only a created mystery , created by current mathematics, not a real mystery. It is obvious that we need a predictive calculus , which should be easy and many of you are chasllenged to the same
.
XYZ (3coordinates to the calculus)
(Z>Y>X)>series progression

Main Condition of the Calculus of Prime numbers, and the half- line 18
(X*Y)+Y*[(Y+Z)-(X+Y)] =Y*Z
The calculus is infinite Z>

Examples:

A. half-line values at 18(6*3) calculus. These values are at 29,31,47,53,61,71,79,101,157,173,191,193??..

(29*31)+31*[(29+31)-(31+47)] = (31*47)
(31*47)+47*[(47+53)-(47+31)] = (47*53)
(47*53)+53*[(53+61)-(47+53)] = (53*61)
(53*61)+61*[(71+61)-(53+61)] = (61*71) so on infinite

B. General Prime numbers calculus:5,7,11,13,17,19,23,29,31,37,41,43,47???..

Example starting at Prime number 19
(19*13)+19*[(19+29)-(19+13)]=(19*29)
19*29+29*[(29+37)-(19+29)]=29*37
(29*37)+37*[(37+43)-(29+37)]=(37*43)?.so on infinite

Vinoo Cameron .

Date Subject Author
5/7/13 HOPEINCHRIST
5/7/13 Don Redmond
5/7/13 trj