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Topic:
Floor of the log equation: s = (floor(log10(x))+1)*x  round((10^(floor(log10(x))+1)10)/9)
Replies:
4
Last Post:
May 22, 2013 11:09 PM




Floor of the log equation: s = (floor(log10(x))+1)*x  round((10^(floor(log10(x))+1)10)/9)
Posted:
May 19, 2013 2:20 PM


Hi guys! I need your help to solve this equation:
I need to find 'x' for a given 's'. Both of them are natural numbers (>0).
I don't know how to handle the floor term.
[octave/matlab format] s = (floor(log10(x))+1)*x  round((10^(floor(log10(x))+1)10)/9);
[or TeX} s = \left( \lfloor\log(x)\rfloor+1 \right)x  \frac{10^{\lfloor\log(x)\rfloor+1}10}{9}
[or image] http://postimg.org/image/r5fd2enll/
Exact or approximate values are good.
Is there a solution? How do I solve it?
Are there any methods to search & find a solution?
Regards,
Carlos



