> Conjecture in Projective geometry. > > Slope of Pascal line GHK can be expressed in terms of > four slopes of lines AB, BC, DE and EF in the first > figure of: > > http://en.wikipedia.org/wiki/Pascal%27s_theorem > > TIA for proof or its contradiction. > > Regards > Narasimham
Narasimham, I might be missing something, the proof seems trivial (except for the special case of parallel lines). Lines AB and DE cross at point G Lines BC and EF cross at point K
Solve for points G and K, then determine slope of line GK.