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Luis A. Afonso
Posts:
4,743
From:
LIsbon (Portugal)
Registered:
2/16/05


Re: 1/E[x] VS E[1/x]
Posted:
Jun 27, 2013 3:40 PM


it sould be a density f(x) such that:
INTG(inft, +inft)1/x * f(x) dx = = 1/[INTG (inft, +inft) f(x) dx
which is impossible.
The Richard Ulrich´s that it will be a Cauchy distribution is absolutely amazing. Ask him at what he based this assumption . . . The only thing that is true is that Cuachy is the ratio between two normal standard. Note else.



