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Topic: 1/E[x] VS E[1/x]
Replies: 3   Last Post: Jun 27, 2013 3:40 PM

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Luis A. Afonso

Posts: 4,615
From: LIsbon (Portugal)
Registered: 2/16/05
Re: 1/E[x] VS E[1/x]
Posted: Jun 27, 2013 3:40 PM
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it sould be a density f(x) such that:

INTG(-inft, +inft)1/x * f(x) dx =
= 1/[INTG (-inft, +inft) f(x) dx

which is impossible.

The Richard Ulrich´s that it will be a Cauchy
distribution is absolutely amazing. Ask him at
what he based this assumption . . .
The only thing that is true is that Cuachy is the ratio
between two normal standard. Note else.



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