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Topic: Making (a*\[Theta]11)/(1+a^2) into (a/(1+a^2))*\[Theta]11
Replies: 1   Last Post: Jun 26, 2013 12:59 AM

 David Park Posts: 1,560 Registered: 5/19/07
Re: Making (a*\[Theta]11)/(1+a^2) into (a/(1+a^2))*\[Theta]11
Posted: Jun 26, 2013 12:59 AM

You have to use something like HoldForm and this may or may not interfere
with further calculation.

You could use:

a \[Theta]11/(1 + a^2);
% /. (r = Coefficient[%, \[Theta]11]) :>

a/(1+a^2) \[Theta]11

The TraditionalForm is necessary to get the desired order of the two
factors.

With the Presentations Application you could use:

<<Presentations`

a \[Theta]11/(1 + a^2) //

a/(1+a^2) \[Theta]11

And I'm sure you'll get a number of other answers.

David Park
djmpark@comcast.net
http://home.comcast.net/~djmpark/index.html

Hi, I have a formatting question.

In the output of an equation I am getting the term (a*\[Theta]11)/(1+a^2).
However, \[Theta]11 is the variable of interest here, and I would like the
term to be written as as a coefficient times \[Theta]11 and not include
\[Theta]11 in the ratio. That is, I would like the output to read
(a/(1+a^2))*\[Theta]11 instead. Does anyone have an idea of how I might be
able to do this? Thanks.