Virgil
Posts:
8,833
Registered:
1/6/11


Re: Solving rational polynomials
Posted:
Aug 17, 2013 4:26 AM


In article <0388f571326f437f990fb3000253e952@googlegroups.com>, Kobu <kobu.selva@gmail.com> wrote:
> Thm: Let p and q be functions. Then, > p(x)/q(x) > 0 iff p(x)*q(x) > 0
Not quite, since when q(x) = 0, p(x)/q(x) is not defined whereas whereas p(x)*q(x) is defined and zero, so "p(x)/q(x) > 0" is indeterminate but "p(x)*q(x) > 0" is false 

