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Topic: what has your CAS to say about this complex equality
Replies: 9   Last Post: Oct 17, 2013 12:03 PM

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A N Niel

Posts: 2,244
Registered: 12/7/04
Re: what has your CAS to say about this complex equality
Posted: Oct 16, 2013 12:15 PM
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In article <525C3859.9FE922D5@freenet.de>, <clicliclic@freenet.de>
wrote:

> Over which extended region of complex numbers a and b does the relation
>
> ABS(a^2*ABS(b - a)^2 + ABS(a)^2*(b^2 - a^2))
> = ABS(a)*ABS(b - a)*(ABS(a)^2 + ABS(b)^2 - ABS(b - a)^2)
>
> hold?
>
> Martin.


how about: a=0 or Re(b/a) >= 0.



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