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Topic: Considering exponentiation when both 0 and 1 are omitted
Replies: 6   Last Post: Nov 7, 2013 11:31 PM

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Registered: 12/4/12
Re: Considering exponentiation when both 0 and 1 are omitted
Posted: Nov 7, 2013 10:38 PM
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On 11/7/2013 9:22 PM, Space998@hotmail.com wrote:
> that is the thing I was looking for

>> 0 = lim(n->oo) 0^(1/n) = 0^0
>> 1 = lim(n->oo) (1/n)^0 = 0^0

I remember.

Glad you found it.

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