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Topic: Eigenvector problem
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Kyle

Posts: 4
From: Seattle
Registered: 11/9/13
Eigenvector problem
Posted: Nov 9, 2013 3:06 PM
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For the case where -x^3+8*x^2-16*x=0 the two roots wolfram alpha gives is x=0 and x=4. But, there is a third root that is cancelled out from factoring and dividing into 0, which could represent any real number. Could this eigenvalue or root represent an infinite number of eigenvectors?



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