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Topic: How the decimal system can do All Possible Digit Arrangements #93
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plutonium.archimedes@gmail.com

Posts: 8,758
Registered: 3/31/08
How the decimal system can do All Possible Digit Arrangements #93
Posted: Dec 20, 2013 9:13 PM
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Only the number 10 as the decimal system can incorporate a Infinity border and a completeness of all the numbers as "All Possible Digit Arrangements".

For example the 10 Grid is this
0
0.1
0.2
0.3
.
.
.
9.7
9.8
9.9
10.0

Now in the binary system of base 2 such as the 8 Grid in base 2, cannot list all the numbers that are All Possible Digit Arrangements.

In True Math, we find the Infinity border to be 1*10^603 and we have a 10^603 Grid where we have 603 digits rightward of the decimal point and 603 digits leftward of the decimal point, that Every Possible Digit Arrangement is produced from the inverse of 1*10^603 as 1*10^-603 and then by Mathematical Induction we successively add 1*10^-603.

In the Binary system we do have a inverse and mathematical induction of that specific inverse, but the system fails to produce all possible digit arrangements.

Is there a reason that only the Decimal System produces Completeness of Numbers (Completeness of the Galois Field)?

The reason I believe what makes 10 do this, is the fact that 10 is composed of two primes 2x5 and that the 5 is crucial to the Logarithmic Golden Mean Spiral as the number phi = (1+sqrt5)/2 = 1.61.. and that the square root of 10 is 3.16.. which is the upper bound of pi = 3.14... Put in layman's terms, 10 is the unique number in mathematics that makes math go round and round in circles or spirals. Any other number for a number-system does not have that feature of being the "go around, turn around" number.

Now how is Binary, base 2 prevented from "every possible digit arrangement"? Well, it requires two binary-points to distinguish the zeroes rightward of the whole number and that second binary-point causes the system to be unable to have all possible digit arrangements.

AP




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