"Bruno Luong" <firstname.lastname@example.org> wrote in message <email@example.com>... > "Dahnial" wrote in message <firstname.lastname@example.org>... > This 0 < C1 < 10 an open interval. 0.1*a <= C1 * 10*a is a close interval, whatever the value of a. Pick your choice. Simplify the problem as you did just make a well-posed problem to an ill-posed one. > > Bruno
Hi Bruno, Thanks for your response Then my apologize to mistakenly state my problem. and yes, the real constraint about my problem is: (let say the initial value of C1 is a) 0.1*a < C1 < 10*a so that means C1 can be any value inside that interval. can we say this as a closed interval?
do you have any suggestion on how should i do my problem(optimize the function-that contains matrix)?