
Re: Polynomial (not quite) division
Posted:
Jan 16, 2014 5:05 AM


> Hi, could anyone please help me with the following: > As an example I'll start with the identity: > > (1 + x^2)(x^3 + 1) = x^3 + x + 1 + x^2 > > Now if I were to use the standard polynomial division algorithm (I > appreciate that x^2 + 1 is not a polynomial) to work out > > (x^3 + x + 1 + x^2) / (x^3 + 1)
= (x^5 + x^3 + x^2 + 1)/(x^5 + x^2) = 1 + (x^3 + 1)/(x^5 + x^2) = 1 + (x^3 + 1)/(x^2 (x^3 + 1)) = 1 + x^2

