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Topic: gravity begins with the proton
Replies: 7   Last Post: Aug 16, 2014 12:29 PM

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haroldj.l.jones@gmail.com

Posts: 61
Registered: 3/17/12
Re: gravity begins with the proton
Posted: Jul 19, 2014 12:49 PM
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The magic of 1.08823067x10^9 and what to name it.

It is c(qa) or c times 3.62994678 in SI units.
It emerges from Ch/4, 4.966118653x10^-26, the G(Mpl)^2 product where Mpl is equal to the Planck mass. 1/4.966118653x10^-26=2.013645x10^25. (2.013645x10^25)^0.3333r
is equal to 2.72057667x10^9. Multiply this by 4 and you have 1.08823067x10^9.
If you multiply our SI system's timescale mass GM structure, 6.7360006x10^24, by
(2.72057667x10^9)^3 you arrive at c^2/h or 1.356391399x10^50. This new Gm structure differs from an SI system structure in that its local mass unit is 2.72057667x10^9 lighter than the kilogram and local c is greater by 2.72057667x10^9 but the metre is the same as the SI system. Think of the CGS system. In such a system the the local GMpl^2 GM structure amounts to one.
Therefore local Planck mass approximates to the proton opposite's Gm product, 29.6906036, divided by 4 or 7.4226509. Square this and you get 55.09574638.
Therefore local G must equal the inverse of this. If we double this to 110.1014928 we have a value that is related to 1.10194453. This is how:

There is a number at the heart of physics I call the quantum number. It approximates to 8.17934956. One of its functions is to convert c into the Planck
mass, 8.17934956/c=Mpl. In my past list of Gc templates I substituted 2/c for G
to give an analogue of the Planck mass of 2.72837394x10-9. Multiply this by c and you have 0.81794593. Multiply h by 2(c/2)^4=0.66903556 and the square root of this is 0.8179459. 0.66903556x2=1.3380711 and the cube root of this is 1.10194453. divide this by 2 and you have 0.550972265 and the square root is 0.74227506 an analogue of 29.6906036/4. And 7.4227506 divided by our analogue Planck mass, 2.72837394x10^-9 comes to 1.08823067x10^9. An obvious parallel match.

All of physics seems to be about replicating numerically what we see. We are no closer to understanding what we see than scientific thinkers were in Newton's time. Take the Rydberg energy, somewhat later than Newton but empirically put together, 2.17987417x10^-18 J. Then take the Gm product GMpl^2, hc/4, 4.966118653x10^-26. Multiply by 2c and you have 7.444024589x10^-18. Divide this by the Rydberg energy, 2.17987417x10^-18 and you have 3.41488728. This number just happens to be the local quantum adjustor for another system where the local mass unit is 1.062977 times lighter than the kilogram hence 3.41488728x1.062977=3.62994678 and 4/3.62994678=1.10194453. So why is this? You could say it's the wrong equation. Take a look:

What we have here is what seems to be and what actually is in the nature of being.
We seem to be dealing with the Gm product, GMpl^2, 4.966118653x10^-26. This numerical value when divided by the proton opposite's Gm product, 29.6906036,
comes to 1.672623x10^-27, the proton mass and therein lies the answer to the riddle. It is not directly about GMpl^2 this time but it does involve the Planck mass.

It is about difference between the Planck energy, (Mpl)c^2 and the Rydberg energy, 2.452107x10^9/2.179874x10^-18=5.62442419x10^26. The problem might be better understood if we look at the reciprocal, 1.777959779x10^-27. This value is 1.062977 greater than the proton mass. What the formula was trying to do was
multiply the Planck energy by 1.777959779x10^-27 which of course comes to the Rydberg energy, total energy this time. But what you must know is that the Planck energy has another composition. It is 29.6906036/3.62994678 and then multiplied by c. So it goes through the same procedure but with 1.777959779x10^-27 instead of the proton mass.

If we take another look at this number, 3.4148874, we can still find a relationship with the SI system.
29.6906036/3.62994678=8.17934956 which approximates to the quantum number. Divide this by 3.4148874 and we find 1.19760167. Where does this come from?
We arrive at the Rydberg energy as follows:

The Rydberg constant, 1.0973732x10^7xcxh. But this is the same as writing it down as:

1.0973732x10^7 x GMpl^2 x 4. What this tells us is there is a close numerical bond between the Planck mass and the nominal values of energy.
If we take away G we arrive at 4x1.0973732x10^7 xMpl^2=Planck mass multiplied by 1.19760167. So that's where it came from.









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