Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: Can you confirm if this equation can be solved for "i" algebraically
Replies: 18   Last Post: Jun 11, 2014 1:14 AM

 Messages: [ Previous | Next ]
 Pubkeybreaker Posts: 1,683 Registered: 2/12/07
Re: Can you confirm if this equation can be solved for "i" algebraically
Posted: Jun 9, 2014 12:49 PM

On Monday, June 9, 2014 12:31:47 PM UTC-4, Abraham A wrote:
> On Monday, June 9, 2014 11:54:03 AM UTC-4, Pubkeybreaker wrote: > On Monday, June 9, 2014 11:46:59 AM UTC-4, Abraham A wrote: > > >> On Monday, June 9, 2014 11:31:10 AM UTC-4, Pubkeybreaker wrote: > On Monday, June 9, 2014 11:05:37 AM UTC-4, Abraham A wrote: > > > <snip> You are correct, it is an Nth degree polynomial > > > >

<snip>

>>Indeed. Please tell us what terms (i.e. degrees) are missing. i.e. what > > coefficients are zero.
>>

Let x = 1+i The present value of annuity equation turns out to be ax^(N+1) + bx^N + c = 0 a, b and c are coefficients of the (N+1), (N) and (0) order terms respectively. All other terms from (N-1) to (1) have coefficients of 0

This is NOT a polynomial in i.

Date Subject Author
6/9/14 Abraham A
6/9/14 Pubkeybreaker
6/9/14 Abraham A
6/9/14 Abraham A
6/9/14 thenewcalculus@gmail.com
6/9/14 Abraham A
6/9/14 Abraham A
6/9/14 thenewcalculus@gmail.com
6/9/14 Pubkeybreaker
6/9/14 Abraham A
6/9/14 Pubkeybreaker
6/9/14 Abraham A
6/9/14 Pubkeybreaker
6/9/14 Abraham A
6/10/14 William Elliot
6/10/14 Abraham A
6/10/14 William Elliot
6/10/14 Abraham A
6/11/14 thenewcalculus@gmail.com