
Re: Can you confirm if this equation can be solved for "i" algebraically
Posted:
Jun 9, 2014 12:49 PM


On Monday, June 9, 2014 12:31:47 PM UTC4, Abraham A wrote: > On Monday, June 9, 2014 11:54:03 AM UTC4, Pubkeybreaker wrote: > On Monday, June 9, 2014 11:46:59 AM UTC4, Abraham A wrote: > > >> On Monday, June 9, 2014 11:31:10 AM UTC4, Pubkeybreaker wrote: > On Monday, June 9, 2014 11:05:37 AM UTC4, Abraham A wrote: > > > <snip> You are correct, it is an Nth degree polynomial > > > >
<snip>
>>Indeed. Please tell us what terms (i.e. degrees) are missing. i.e. what > > coefficients are zero. >> Let x = 1+i The present value of annuity equation turns out to be ax^(N+1) + bx^N + c = 0 a, b and c are coefficients of the (N+1), (N) and (0) order terms respectively. All other terms from (N1) to (1) have coefficients of 0
This is NOT a polynomial in i.

