The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » sci.math.* » sci.math

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: 2.36 - Proof without limits or calculus.
Replies: 11   Last Post: Jul 31, 2014 10:17 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Scott Berg

Posts: 2,111
Registered: 12/12/04
Re: 2.36 - Proof without limits or calculus.
Posted: Jul 29, 2014 2:32 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

On 7/29/2014 1:22 PM, John Gabriel wrote:
> If f(x)=px+q, then prove that for a given interval (a,b), the average value of all the ordinates of f is:
> { f(a)+f(b) } / 2 = { pa+q+pb+q } / 2 = p(a+b)/2 + q

what do the { and } mean ?? do you mean ( and ) ?

did you make mistake ?

also you proved that f(a)+f(b) = f(a + b),

how can that be ?

> You may NOT use limits or any of the theorems of calculus.

no need, this is simple algebra.

> The ordinates must either be all positive or all negative.


> I might respond to comments on this thread or I might not.

or you will almost not respond, or sort of think about responding, but
your thinking is confuseded, do you have a pet dog ?
Sometimes a pet dog will take over your thinking.

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.