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Topic: ? 533 Proof
Replies: 46   Last Post: Aug 4, 2014 8:39 PM

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Registered: 1/29/05
Re: ? 533 Proof
Posted: Aug 3, 2014 4:51 PM
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On Sunday, 3 August 2014 16:38:53 UTC+2, V I R G I L wrote:

> What |N does that no finite initial segment of |N does is contain ALL
> finite initial segments of |N as proper subsets, so |N does things that
> no finite initial segment of |N can do.

And for just all these finite initial segments I have shown that they leave infinitely many, in fact increasingly many, rationals without index. Whereas you show your enumerations only for some 10 naturals. Feeble.

Regards, WM

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