On Tuesday, August 12, 2014 12:55:12 PM UTC-7, muec...@rz.fh-augsburg.de wrote: > On Tuesday, 12 August 2014 19:56:40 UTC+2, Zeit Geist wrote: > > On Tuesday, August 12, 2014 8:57:12 AM UTC-7, muec...@rz.fh-augsburg.de wrote:
> > > Cantor's proof requires that there is a point of time where the sequence is "closed".Then the anti-diagonal is constructed.
> > Hmmm, I must Missed the Variable t, for Time, in Cantor's Proof. > > Can you Show where he says, "Let t Stand for Time."? > > He denies that the list, after constructing the diagonal, may be expanded such that every element goes from n to 2n, such that infinitely many lines become empty. >
Yep, the List is Chosen and then does Not Change. So where is that t?
I think your Really Lost or just Grasping at Straws.
> > > But there is no reason to assume the sequence as "closed". In fact, as I have shown in § 533, this is a false assumption.
> > You have Shown Nothing but a Result for Finite Sets!
> For all FIS with no upper bound. More is not possible to show.
For Any FIS, sure. Which is All of them. But you Never Show a How the Result Follows. The Result After is Considering a Bijection between Infinite Sets.
For any FIS, say f, there Exists a Natural Number m such that m > Card(f). Does such a Number Exist such that For Every FIS, say g, we have m > Card(g). No! Why? Because For Every m e N there exist a FIS, g, such that m <= Card(g).
Same with the Enumeration of the Rationals. Up to Every n, the Function Leaves Infinitely Many q Unenumerated. However, no q is Left Unenumerated Up to Every n.
No Contradiction. This is just your Deep Misunderstands giving you False Results, which you feel you Must share with us.