Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: How stupid is John Gabriel: little stupid, stupid or very stupid?
Replies: 4   Last Post: Nov 8, 2017 9:37 PM

 Messages: [ Previous | Next ]
 Jan Burse Posts: 1,472 Registered: 4/12/05
How stupid is John Gabriel: little stupid, stupid or very stupid?
Posted: Nov 2, 2017 1:49 PM

Ok, lets make a test, he repeatedly claims:

1) New calculoose
2) Constructive proof for MVT
3) Real numbers don't exist

Lets see whether these fit together, so we begin
with the MVT, I guess he proved, and since the
proof is constructive but not the MVT, I guess
its the usual MVT, so there exists c such that:

f(b) - f(a)
f'(c) = -----------
b - a

Now lets use new calculoose, I guess he has
also an antiderivative, so we begin with
choosing a function f(x) as follows:

f(x) = integ_0^x g(y) dy

Plug it into MVT and we get, there exist c such that:

integ_a^b g(y) dy
g(c) = -----------------
b - a

Now lets try what we get for:

g(y) = 1/(1+y^2)

a = 0

b = 1

We get:

1/(1+c^2) = atan(1) - atan(0) = pi/4

Which gives the following c, whose existence is assured
by the MVT, namely:

c = sqrt(4/pi - 1) = 0.522723...

Since pi is transcendental its surely an irrational
number. And lets repeat JGs claim, there is an MVT,
hence c exists.

But now lets look at the last claim of JG, real
numbers do not exist, so we clearly have a

Conclusion: very stupid

Date Subject Author
11/2/17 Jan Burse
11/2/17 Jan Burse
11/2/17 zelos.malum@gmail.com
11/8/17 bursejan@gmail.com
11/8/17 Me