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How stupid is John Gabriel: little stupid, stupid or very stupid?
Posted:
Nov 2, 2017 1:49 PM


Ok, lets make a test, he repeatedly claims:
1) New calculoose 2) Constructive proof for MVT 3) Real numbers don't exist
Lets see whether these fit together, so we begin with the MVT, I guess he proved, and since the proof is constructive but not the MVT, I guess its the usual MVT, so there exists c such that:
f(b)  f(a) f'(c) =  b  a
Now lets use new calculoose, I guess he has also an antiderivative, so we begin with choosing a function f(x) as follows:
f(x) = integ_0^x g(y) dy
Plug it into MVT and we get, there exist c such that:
integ_a^b g(y) dy g(c) =  b  a
Now lets try what we get for:
g(y) = 1/(1+y^2)
a = 0
b = 1
We get:
1/(1+c^2) = atan(1)  atan(0) = pi/4
Which gives the following c, whose existence is assured by the MVT, namely:
c = sqrt(4/pi  1) = 0.522723...
Since pi is transcendental its surely an irrational number. And lets repeat JGs claim, there is an MVT, hence c exists.
But now lets look at the last claim of JG, real numbers do not exist, so we clearly have a classical contradiction.
Conclusion: very stupid



