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Topic:
A limit at a point means a function is continuous at that point, but orangutans still don't get it!
Replies:
10
Last Post:
Nov 12, 2017 3:09 PM




A limit at a point means a function is continuous at that point, but orangutans still don't get it!
Posted:
Nov 9, 2017 7:49 AM


There is **no limit** to e^(1/(x^2)) as x approaches 0.
The idiotic mainstream tendency is to transfer the limit to the exponent, that is,
oo = Lim_{x \to 0} 1/(x^2)
in which case we say there is no limit because oo is NOT a limit.
Then what do orangutans do? They say:
0=e^(oo)
treating infinity exactly as if it were a number. Chuckle. I wonder ... does the limit operator jump back and forth between the exponent and e ....
As I've stated in the past and continue to state, you cannot have a HOLE in a function at a point c in an interval (a,b) if the function is continuous on the interval and has a limit at c. The bogus mainstream calculus NEEDS holes, but even then, it needs a lot more decrees to stay afloat.
Therefore, the function e^(1/(x^2)) has NO limit at x=0 otherwise it would be continuous at x=0.
And you thought Swiss cheese was holey eh?!
Wolfram computational engine states that the limit is 0. Tsk, tsk. Idiots...
Eat shit and die Mr. Penis Messager (Jean Pierre Messager / alias Python).



