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A PROBLEM THE BOOK IS WRONG AT!!!
Posted:
Nov 17, 1999 12:24 PM


I EMAILED THIS TO MY TEACHER. PLEASE LOOK OVER THIS AND TELL ME WHAT I DID IS RIGHT!!
Mr. Blundell,
I did #22 in exercise 4.3 and I feel that your answer you gave me at end of class is wrong. The way I feel this way is because of the wording of the question.
question was:
How MANY WAYS ARE THERE TO SELECT A COMMITEE of five members of the department if at least 1 woman must be on the commitee?
When it says "MANY WAYS ARE THERE TO SELECT A COMMITEE" it doesn't mean "HOW MANY COMMITEE'S CAN BE SELECTED". The two are 2 different things.
EX:
SUE was 1st FRED was 2nd JOE was 3rd ED was 4th Kathy was 5th
This set is 1 way to pick the commitee and on the other hand:
FRED was 1st SUE was 2nd Joe was 3rd ED was 5th Kathy was 6th
Even thou these are the same committes they were elected to the commitee in a different way. Isn't that right??
So if you had 7 women and 9 men wouldnt it be like this for the answer.
7W * 9M * 8M * 7M * 6M= 21168 WAYS correct? 7W * 6W * 9M * 8M * 7M= 21168 WAYS correct? 7W * 6W * 5W * 9M * 8M= 15120 WAYS correct? 7W * 6W * 5W * 4W * 9M= 7560 WAYS correct? 7W * 6W * 5W * 4W * 3W= 2520 WAYS correct? 9M * 7W * 6W * 5W * 4W= 7560 WAYS correct? 9M * 8M * 7W * 6W * 5W= 15120 WAYS correct? 9M * 8M * 7M * 7W * 6W= 21168 WAYS correct? 9M * 8M * 7M * 6M * 7W= 21168 WAYS correct?
Then if you add all the ways together it equals= 132552
Please email me and tell me what the way to do it if I am wrong because the wording of the question asks "HOW MANY WAYS" not "HOW MANY COMMITTES". 2 different ideas.
EDDIE PEREZ eperez@worldinter.net
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