Math Forum Discussions

paul c

Posts: 3
Registered: 12/6/04

[No Subject]
Posted: Mar 21, 2000 4:38 AM

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denise,

you need to show the following steps:

n(n+1)(n+2)(n+3)/4 + (n+1)(n+2)(n+3) = [n(n+1)(n+2)(n+3) +
4(n+1)(n+2)(n+3)]/4

factoring (n+1)(n+2)(n+3) in the numerator, we get the desired expression
(n+1)(n+2)(n+3)(n+4)/4.

paul cabral
assistant software engineer
adtex-philippines, inc.

p.s.
enjoy diversity in all forms!

From: Denise <DCamillo@aol.com> | Block address
To: discretemath@forum.swarthmore.edu
Date: Sun, 19 Mar 2000 16:57:41 +0000
Subject: Mathematical Induction
Add Addresses

Need to show by induction:
1*2*3+2*3*4+...n*(n+1)*(n+2)=n*(n+1)*(n+2)*(n+3)/4. Please help!!!!!!
Email me at DCamillo@aol.com, Thanks.