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Re: math paradox
Posted:
Jan 7, 1998 5:00 AM


NATHANIEL SILVER wrote:
> > 1=(1)^3=(1)^(6/2)=sqrt((1)^6)=sqrt(1)=1
> (1)^(6/2)=sqrt((1)^6) is not true.
Ok.
> When real number b < 0, then b^(m/n) = (b^m)^(1/n) and b^(m/n) = > (b^(1/n))^(m) hold, if m/n is reduced to lowest terms. > > That's why calculators operations are defined (only when x >= 0) for > (x^(1/n))^m, (x^m)^(1/n), and not for x^(m/n). The user takes it from there > with the absolute value key (and split domains for functions). > > In a similar conundrum, (8)^(1/3) is not equal to (8)^(2/6).
I think they are equal. (If not, what's the difference according to you?) > Dr. Dunce
Wilbert



