Hi, I iterated x <=> 2^(1/x), as Ed Wall suggested, 350 iterations using mathematica produced: 1.55961046946236958`^1.55961046946236958`=2.
You could quite easily do this iteration in a spreadsheet like Excel or Quattro Pro
Ed Wall wrote:
> Well, Newton's method converges fairly rapidly. That is, work with > > x2=2^(1/x1) > > However, it seems like one could do something nicer than that. How about > > x^x = .2 :-) > > Ed > > At 5:44 AM -0500 2/21/99, Russ256 wrote: > >Can anybody solve the following equation for me: x^x = 2. I've tried > >everything from logarithms to powers, but nothing seems to work. Thanks in > >advance. > > > > -Russell (Russ256@aol.com)