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Re: Difficult Power Problem
Posted:
Feb 21, 1999 11:21 PM
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Hi,
I iterated x <=> 2^(1/x), as Ed Wall suggested, 350 iterations using mathematica
produced: 1.55961046946236958`^1.55961046946236958`=2.
You could quite easily do this iteration in a spreadsheet like Excel or Quattro
Pro
Regards,
Jon Roberts.
Ed Wall wrote:
> Well, Newton's method converges fairly rapidly. That is, work with
>
> x2=2^(1/x1)
>
> However, it seems like one could do something nicer than that. How about
>
> x^x = .2 :-)
>
> Ed
>
> At 5:44 AM -0500 2/21/99, Russ256 wrote:
> >Can anybody solve the following equation for me: x^x = 2. I've tried
> >everything from logarithms to powers, but nothing seems to work. Thanks in
> >advance.
> >
> > -Russell (Russ256@aol.com)
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