Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
Drexel University or The Math Forum.



Re: Difficult Power Problem
Posted:
Feb 21, 1999 11:21 PM


Hi, I iterated x <=> 2^(1/x), as Ed Wall suggested, 350 iterations using mathematica produced: 1.55961046946236958`^1.55961046946236958`=2.
You could quite easily do this iteration in a spreadsheet like Excel or Quattro Pro
Regards,
Jon Roberts.
Ed Wall wrote:
> Well, Newton's method converges fairly rapidly. That is, work with > > x2=2^(1/x1) > > However, it seems like one could do something nicer than that. How about > > x^x = .2 :) > > Ed > > At 5:44 AM 0500 2/21/99, Russ256 wrote: > >Can anybody solve the following equation for me: x^x = 2. I've tried > >everything from logarithms to powers, but nothing seems to work. Thanks in > >advance. > > > > Russell (Russ256@aol.com)



