In a /\ABC,BD and CE are the internal bisectors of B^ and C^.If BD=CE Prove that AB=AC. The solution is governed by the following two conditions. A /\ E / \D / \ /______\ B C 1. Reduction ad Absurdum should not be used. 2. Proof must be by purely geometry techniques.No other branch of Maths like Trigonometry,Vectors etc must be used.Proof must be by pure geometry concepts.
I would appreciate any response to my address email@example.com