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Topic: Triangle Proof II
Replies: 4   Last Post: Jun 30, 2004 8:13 AM

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Michael Lambrou

Posts: 70
Registered: 12/3/04
RE: Triangle Proof II
Posted: Jun 30, 2004 4:59 AM
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> -----Original Message-----
> From: [mailto://owner-geometry-
>] On Behalf Of Eamon
> Sent: Wednesday, June 30, 2004 7:08 AM
> To:
> Subject: Triangle Proof II
> ABC is an ARBITRARY triangle.
> D lies on BC and E lies on AC.
> Prove that if AD = BE then the triangle is isosceles.
> y| C
> | /\
> | / \
> | / \ D
> | E/ \
> | / \
> | / \
> ____|/__________________\B____
> A| x

The result is of course false. More conditions should be added.

Example: Take a non-isosceles triangle ABC.
From A draw a circle of arbitrary radius cutting BC at D (plus another
point). With the same radius draw a circle with B as centre,
cutting AC at E (plus another point). That does it.
Note, there is an abundance of such radii. All you need is to pick a
length greater than the largest of the altidudes of the triangle.

Michael Lambrou

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